[swift-users] is this a defect in equatable for swift tuples?

[David Baraff]

> On Jul 9, 2017, at 8:16 AM, Adrian Zubarev <adrian.zubarev at devandartist.com> wrote:
> 
> Easy: class SomeClass : Equatable {
> 
> 
Doh!!

thank you.

> 
> 
> -- 
> Adrian Zubarev
> Sent with Airmail
> 
> Am 9. Juli 2017 um 17:11:14, David Baraff via swift-users (swift-users at swift.org <mailto:swift-users at swift.org>) schrieb:
> 
>> Given 2-tuples of type (T1, T2), you should be able to invoke the == operator if you could on both types T1 and T2, right?  i.e.
>> 
>> (“abc”, 3) == (“abc”, 4) // legal
>> 
>> but:
>> 
>> class SomeClass {
>>     static public func ==(_ lhs:SomeClass, _ rhs:SomeClass) -> Bool {
>>         return lhs === rhs
>>     }
>> }
>> 
>> let c1 = SomeClass()
>> let c2 = SomeClass()
>> 
>> let t1 = ("abc", c1)
>> let t2 = ("abc", c2)
>> 
>> c1 == c2 // legal
>> t1 == t2 // illegal
>> 
>> 
>> 
>> 
>> Why is t1 == t2 not legal given that c1 == c2 IS legal?
>> 
>> 
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>> https://lists.swift.org/mailman/listinfo/swift-users
> 
> 

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