[swift-users] is this a defect in equatable for swift tuples?

[Adrian Zubarev]

Easy: class SomeClass : Equatable {


-- 
Adrian Zubarev
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Am 9. Juli 2017 um 17:11:14, David Baraff via swift-users (swift-users at swift.org) schrieb:

Given 2-tuples of type (T1, T2), you should be able to invoke the == operator if you could on both types T1 and T2, right?  i.e.

(“abc”, 3) == (“abc”, 4) // legal

but:

class SomeClass {
    static public func ==(_ lhs:SomeClass, _ rhs:SomeClass) -> Bool {
        return lhs === rhs
    }
}

let c1 = SomeClass()
let c2 = SomeClass()

let t1 = ("abc", c1)
let t2 = ("abc", c2)

c1 == c2 // legal
t1 == t2 // illegal




Why is t1 == t2 not legal given that c1 == c2 IS legal?


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