[swift-users] Hexadecimal floating-point literals

Toni Suter tonisuter at me.com
Sun Jun 26 22:34:32 CDT 2016


Ok, thanks for the hint!

Toni

> On 26 Jun 2016, at 11:49, zh ao <owenzx at gmail.com> wrote:
> 
> I think it avoids the confusion. You can use print((0xabc).beef) instead.
> 
> Zhaoxin
> 
> On Sun, Jun 26, 2016 at 3:50 PM, Toni Suter via swift-users <swift-users at swift.org <mailto:swift-users at swift.org>> wrote:
> Hi,
> 
> I have a question regarding hexadecimal floating-point literals. According to the Lexical Structure (https://developer.apple.com/library/prerelease/content/documentation/Swift/Conceptual/Swift_Programming_Language/LexicalStructure.html <https://developer.apple.com/library/prerelease/content/documentation/Swift/Conceptual/Swift_Programming_Language/LexicalStructure.html>) 
> it is not possible to have a hex floating-point literal without the exponent. At first I thought this makes sense.
> How else would the lexer / parser know if 0x123.beef is a hex floating-point literal or a hex integer literal with a property 'beef'?
> However, if I define such a property on Int, it doesn’t work:
> 
> extension Int {
>     var beef: Int {
>         return 42
>     }
> }
> 
> print(12.beef) 		// works
> print(0b1001.beef) 	// works
> print(0o77.beef) 	// works
> print(0xabc.beef) 	// error: hexadecimal floating point literal must end with an exponent
> 
> Is this just to avoid confusion for the programmer? Or is there some other reason?
> 
> Thanks and best regards,
> Toni
> 
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