[swift-users] super.init() called automatically?

[James Campbell]

Not a big fan of this implict behaviour. Not super obvious.

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On 17 May 2016 at 10:48, tuuranton--- via swift-users <swift-users at swift.org
> wrote:

> Why is this the intentional behavior? Seems a bit strange that init() is a
> special exception to the rule.
>
> 16. May 2016 19:29 by clattner at apple.com:
>
>
>
> On May 16, 2016, at 7:09 AM, tuuranton--- via swift-users <
> swift-users at swift.org> wrote:
>
> Why does the following code compile?
> Why does Bar's init(x: Int) automatically call Foo's init()?
> Why don't I have to manually call super.init() myself?
>
>
> This is intentional behavior.  It kicks in when your super class has a
> single designated initializer with a zero-argument init.  This is why you
> don’t have to call super.init() when deriving from NSObject.
>
> -Chris
>
>
> What passage of
>
> https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/Initialization.html#//apple_ref/doc/uid/TP40014097-CH18-ID203
> tells me that this should be the case?
>
> --------------------
> class Foo {
>     init() {
>         print("foo init")
>     }
> }
> class Bar: Foo {
>     init(x: Int) {
>         print("bar init")
>     }
> }
> let b = Bar(x: 0)
> //prints:
> //    bar init
> //    foo init
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