[swift-users] super.init() called automatically?
tuuranton at tutanota.de
tuuranton at tutanota.de
Tue May 17 04:48:14 CDT 2016
Why is this the intentional behavior? Seems a bit strange that init() is a
special exception to the rule.
16. May 2016 19:29 by clattner at apple.com:
>
>
>> On May 16, 2016, at 7:09 AM, tuuranton--- via swift-users <>>
>> swift-users at swift.org>> > wrote:
>> >> Why does the following code compile?>> Why does Bar's init(x:
>> Int) automatically call Foo's init()?>> Why don't I have to manually call
>> super.init() myself?
>
> This is intentional behavior. It kicks in when your super class has a
> single designated initializer with a zero-argument init. This is why you
> don’t have to call super.init() when deriving from NSObject.
> -Chris
>
>>
>> What passage of>>
>> https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/Initialization.html#//apple_ref/doc/uid/TP40014097-CH18-ID203>>
>> tells me that this should be the case?
>> -------------------->> class Foo {>> init() {>> print("foo
>> init")>> }>> }>> class Bar: Foo {>> init(x: Int) {>>
>> print("bar init")>> }>> }>> let b = Bar(x: 0)>> //prints:>> // bar
>> init>> // foo init>> >>
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>
>
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