[swift-evolution] Infer types of default function parameters
Rien
Rien at Balancingrock.nl
Sat Mar 11 02:01:59 CST 2017
0
Its not something I would use, but I don’t see why not.
Regards,
Rien
Site: http://balancingrock.nl
Blog: http://swiftrien.blogspot.com
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> On 10 Mar 2017, at 22:40, Kilian Koeltzsch via swift-evolution <swift-evolution at swift.org> wrote:
>
> Hi all,
>
> I sent the message below to swift-users@ ~a day ago, but this might be a better place to ask and gather some discussion. It is a rather minor suggestion and I'm just looking for some opinions.
>
> Declaring a function that has default parameters currently looks like this:
>
> func foo(bar: String = "baz") {
> print(bar)
> }
>
> Now I'm wondering if there would be any problems if it were possible to omit the type annotation for default params and let Swift's type inference handle that.
>
> func foo(bar = "baz") {
> print(bar)
> }
>
> It feels to be equivalent to omitting type annotations with variable declarations. Obviously more complex types would still require annotations being specified. Off the top of my head I can't think of any negative ramifications this might bring, be it in simple function/method declarations or protocol extensions and elsewhere.
> Any further input or examples for situations where this might cause issues would be much appreciated :)
>
> Cheers,
> Kilian
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