[swift-evolution] Infer types of default function parameters

[T.J. Usiyan]

-1 from me. I prefer explicitness at function boundaries.

On Fri, Mar 10, 2017 at 4:55 PM, David Sweeris via swift-evolution <
swift-evolution at swift.org> wrote:

>
> On Mar 10, 2017, at 1:40 PM, Kilian Koeltzsch via swift-evolution <
> swift-evolution at swift.org> wrote:
>
> Hi all,
>
> I sent the message below to swift-users@ ~a day ago, but this might be a
> better place to ask and gather some discussion. It is a rather minor
> suggestion and I'm just looking for some opinions.
>
> Declaring a function that has default parameters currently looks like this:
>
> func foo(bar: String = "baz") {
>     print(bar)
> }
>
> Now I'm wondering if there would be any problems if it were possible to
> omit the type annotation for default params and let Swift's type inference
> handle that.
>
> func foo(bar = "baz") {
>     print(bar)
> }
>
> It feels to be equivalent to omitting type annotations with variable
> declarations. Obviously more complex types would still require annotations
> being specified. Off the top of my head I can't think of any negative
> ramifications this might bring, be it in simple function/method
> declarations or protocol extensions and elsewhere.
> Any further input or examples for situations where this might cause issues
> would be much appreciated :)
>
>
> Tentatively +1… I still haven’t thought through it as much as I’d like to.
>
> - Dave Sweeris
>
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>
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