[swift-evolution] Union instead of Optional
Cao Jiannan
frogcjn at 163.com
Sat May 14 21:33:51 CDT 2016
It’s kind of same idea of TypeScipt 2, at 46:21 in this video.
https://channel9.msdn.com/Events/Build/2016/B881 <https://channel9.msdn.com/Events/Build/2016/B881>
>
> 2016-2-16 GMT+8 14:36:28
> Hi all,
>
> I think the best way to solve the either problem is to separate it from generic.
> Optional and Either shouldn’t work the same way of generic type.
> It’s just a represent of multiple type in one location.
>
> Using an old friend, Union in C.
> union {
> case firstType
> case secondType
> }
>
> This is the final solution for the sub typing problem of optional.
>
> A == union(A,A)
> union(A,B) == union(B,A)
> B == union(B,B)
>
> B is subtype of union(A,B)
> A is subtype of union(A,B)
> union(A,B,C) is subtype of union(A,B,C,D,…)
>
> suppose
> a is subclass of A
> b is subclass of B, then
> union(a,B) is subtype of union(A,B)
> union(A,b) is subtype of union(A,B)
> union(a,b) is subtype of union(a,B)
> union(a,b) is subtype of union(A,b)
>
> union can have as many case as possible. e.g., union(A,B,C,D,…)
>
> So the Optional<UITableView> should be union(UITableView, None)
> and Optional<MyTableVIew> should be union(MyTableView, None), which is subclass of union(UITableView, None)
>
> This is a final rational solution. I think.
>
> -Jiannan
>
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