[swift-evolution] Disambiguate Return Type With Void

[Andrew Bennett]

Swift can resolve functions based on the return type. However, when the
result is unused a single function often can't be resolved without
explicitly specifying the type.

func example() { ... }
func example() -> Int { ... }

example() as Void
example() as Int

This proposal disambiguates some cases:

   - Preferring functions with a *Void* return type when the result *is*
   discarded.
   - Preferring functions with a *non-Void* type when the result *is not*
   discarded.

These example will be unambiguous:

example() // will prefer a `Void` function
let x = example() // will prefer a non-`Void` function

You can read the full latest version of the proposal here:

https://github.com/therealbnut/swift-evolution/blob/andrew-disambiguate-return-type/proposals/0000-disambiguate-return-type.md

This is the original version
<https://github.com/therealbnut/swift-evolution/blob/59d0f0b9bdabcfd675f36824232a8efa4a5f9152/proposals/0000-disambiguate-return-type.md>
of
the proposal.
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