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.error { color:#AA0000; }</style></head><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space;"><div class="bloop_markdown"><p>I always wanted a way to make some protocol default implementations not overridable. Now Swift 3 got <code>open</code> vs. <code>public</code> behavior for classes. (Hopefully the inconsistency will be fixed soon and we’ll get <code>open protocols</code> as well.)</p>
<p>Imagine this scenario with <code>open/public protocols</code>.</p>
<pre><code class="swift">// Module A
// `open protocol` means that in a diff. module I'll
// be able to conform to that protocol
open protocol Proto {}
extension Proto {
// shouldn't this mean that the variable is not overridable
// from a different module? :)
public var foo: Int { return 42 }
}
// Module B
struct A : Proto {
// can I or can I not override `foo` from here?
}
</code></pre>
<p>I wonder if my thinking is correct here, or do we need something else to make extensions with default implementation to be fixed and not overridable?</p>
<p></p></div><div class="bloop_original_html"><style>body{font-family:Helvetica,Arial;font-size:13px}</style><div id="bloop_customfont" style="font-family:Helvetica,Arial;font-size:13px; color: rgba(0,0,0,1.0); margin: 0px; line-height: auto;"><br></div><br><div id="bloop_sign_1474014421017753088" class="bloop_sign"><div style="font-family:helvetica,arial;font-size:13px">-- <br>Adrian Zubarev<br>Sent with Airmail</div></div></div><div class="bloop_markdown"><p></p></div></body></html>