[swift-users] Refining generics in classes
Jon Shier
jon at jonshier.com
Wed Nov 15 22:42:48 CST 2017
Swift Users:
I have a generics use case which has somewhat stumped me. I have two related protocols, JSONDecodable and CompressedDecodable, and CompressedDecodable inherits from JSONDecodable (though that relationship isn’t strictly necessary). I also have a generic function that’s overloaded for each of those protocols. I’m trying to write a class to make a network request expecting a generic response type of either JSONDecodable or CompressedDecodable. However, it doesn’t seem possible to write it in such a way that the overload I need is called. Instead, it’s always the superclass’ type’s overload that is called. For example:
protocol JSONDecodable { init() }
protocol CompressedDecodable: JSONDecodable { }
class NetworkRequest<T: JSONDecodable> {
var response: T?
func doAThing() {
response = doSomething()
}
}
class CompressedNetworkRequest<U: CompressedDecodable>: NetworkRequest<U> {
}
func doSomething<T: JSONDecodable>() -> T {
print("One: \(T.self)")
return T()
}
func doSomething<T: CompressedDecodable>() -> T {
print("Two: \(T.self)")
return T()
}
struct Uno: JSONDecodable { }
struct Dos: CompressedDecodable { }
NetworkRequest<Uno>().doAThing()
CompressedNetworkRequest<Dos>().doAThing()
In a playground this prints:
One: Uno
One: Dos
Ultimately, I understand why this happens (NetworkRequest’s generic type is always going to be JSONDecodable, no matter if it’s actually a subtype). Is there any way, aside from completely duplicating the class, to call the overload appropriate for the type passed in a class like this?
Jon Shier
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