[swift-users] How to resolve "type(of: instance)" being shadowed by "instance.type"?

Glen Huang heyhgl at gmail.com
Sat Sep 23 00:13:22 CDT 2017

Ah, how come I never thought about trying that!?



> On 23 Sep 2017, at 1:10 PM, Slava Pestov <spestov at apple.com> wrote:
>> On Sep 22, 2017, at 10:10 PM, Glen Huang via swift-users <swift-users at swift.org> wrote:
>> I have a class like this:
>> class File {
>>  type: FileType
>>  url: URL
>>  func fetch(from server: Server) {
>>      type(of: server).get(from: url)
>>  }
>> }
>> However, it fails to compile with "Cannot call value of non-function type ‘File’” inside the body of fetch(from:). I believe the reason is that self.type shadows  type(of: server).
>> Other than renaming the “type” property, is there any other way to work around it? I tried "Foundation.type(of: server)” and found out that it’s from the standard library and not Foundation. Is there a prefix that denotes the standard library?
> The standard library module is named ‘Swift’, so ‘Swift.type(of:)’ should do the trick.
>> A more general question, since this is clearly a function call, why would it be shadowed by self.type, which is clearly a property access?
>> I’m using Swift 4 in Xcode 9.
>> Regards,
>> Glen
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