[swift-users] XML parsing on Linux, with Swift 3.1

[CK TUNG]

This revised code, as below, works without segmentation fault

import Foundation

class ParserDelegate: NSObject, XMLParserDelegate {
    
    func startParsing(_ xml:String) {
        let data = xml.data(using: .utf8)!
        let xmlParser = XMLParser(data: data)
        xmlParser.delegate = self
        xmlParser.parse()
    }
    
    func parserDidStartDocument(_ parser: XMLParser) {
        print("Starting document")
    }
    
    func parser(_ parser: XMLParser, didStartElement elementName: String, namespaceURI: String?, qualifiedName qName: String?, attributes attributeDict: [String : String]) {
        print("*** \(elementName)")
    }
}

let xml = "<root><title name=\"test\">George</title></root>"
let test = ParserDelegate()
test.startParsing(xml)

On Sep 05, 2017, at 02:24 PM, Georgios Moschovitis via swift-users <swift-users at swift.org> wrote:

As an example, this SegFaults:

import Foundation

class ParserDelegate: NSObject, XMLParserDelegate {
func parserDidStartDocument(_ parser: XMLParser) {
print("Starting document")
}

func parser(_ parser: XMLParser, didStartElement elementName: String, namespaceURI: String?, qualifiedName qName: String?, attributes attributeDict: [String : String] = [:]) {
print("*** \(elementName)")
}
}

let xml = "<root><title name=\"test\">George</title></root>"
let data = xml.data(using: .utf8)!
let xmlParser = XMLParser(data: data)
xmlParser.delegate = ParserDelegate()
xmlParser.parse()

On 5 Sep 2017, at 9:01 AM, Georgios Moschovitis <george.moschovitis at icloud.com> wrote:

Hi,

I would like to parse an RSS feed using Swift 3.1 on Linux.
I tried to use Foundations’s XML but I only managed to get segmentation faults.
Is this supposed to work on Linux? I have only seen examples on iOS.

Apart from that a quick search didn’t reveal any useful XML parsing library compatible with Linux.

Any suggestions?

-g.

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