[swift-users] typealias for Generic in Generic

[Adrian Zubarev]

R is a non generic type, because the generic part is set to T, that’s why R() works.

Otherwise you could create typealias Q<NameThatIsNot_T> = Сarriage<NameThatIsNot_T> and use it like this Q<String>()



-- 
Adrian Zubarev
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Am 4. April 2017 um 19:25:45, Седых Александр via swift-users (swift-users at swift.org) schrieb:

Hello.
I stumbled on ambiguous behaviour of compiler. Is not allowed explicitly indicate type in Generic typealias.



struct Сarriage<T> {
    let g = [T]()
}
 
struct Coma<T> {
    typealias R = Сarriage<T>
    let m = R()
    let d = R<String>() \\ error: cannot specialize non-generic type 'Сarriage<T>'
    var b = Сarriage<String>()
    mutatingfunc work() {
        m.g.append(<#T##newElement: T##T#>) \\ what I can write here?
        b.g.append("Z")
    }
}


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