[swift-users] How to pass a protocol as parameter, without using @objc?

[Zhao Xin]

Great!

Zhaoxin

On Tue, Mar 14, 2017 at 2:15 PM, Bruno Macabeus via swift-users <
swift-users at swift.org> wrote:

> I found the solution. I need use a closure.
> I updated the gist: https://gist.github.com/brunomacabeusbr/
> eea343bb9119b96eed3393e41dcda0c9
>
> 2017-03-13 1:38 GMT-03:00 Bruno Macabeus <bruno.macabeus at gmail.com>:
>
>> Hello,
>>
>> I wrote a gist to list all classes that subscribers a protocol:
>> https://gist.github.com/brunomacabeusbr/eea343bb9119b96eed3393e41dcda0c9
>> It work, but, I could not pass a protocol as parameter, then, I need
>> wrote one function each time I need to list class from different
>> protocol.
>> I know how to pass a protocol using @obcj
>> <http://stackoverflow.com/a/27162499/3440266>, but I can't use @obcj,
>> because my protocols have property.
>>
>
>
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