[swift-users] Function conforming to a typealias

[Adrian Zubarev]

Not sure what you’re trying to solve there but you could use it like this with closures:

typealias Function = (Int, Bool) -> String?

let myGreatFunc1: Function = { _ in return nil /* or whatever you need there */ }
let myGreatFunc2: Function = { _ in return nil }


-- 
Adrian Zubarev
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Am 18. Februar 2017 um 11:47:26, Rien via swift-users (swift-users at swift.org) schrieb:

I want to create a few functions that all have the same signature.

The signature is defined in a typealias

Is there any way to shortcut the function definition, or alternatively ensure that the function signature will always be equal to the typealias?

Examplecode:

typealias Mysig = (Int, Bool) -> String?

func myGreatFunc1:Mysig {…}

func myGreatFunc2:Mysig { …}

Alternatively

@conformsTo(Mysig)
func myGreatFunc1(_ a:Int, _ b: Bool) -> String? {…}

Regards,
Rien

Site: http://balancingrock.nl
Blog: http://swiftrien.blogspot.com
Github: http://github.com/Balancingrock
Project: http://swiftfire.nl





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