[swift-users] Changing precedence of / operator for my protocol?

[Rick Mann]

> On Nov 29, 2016, at 15:22 , Howard Lovatt <howard.lovatt at gmail.com> wrote:
> 
> Why not define some other symbol so that you can get the precedence you want?

I could, but I think I'll just leave things as they are. No need to add confusion; it works to use parentheses.

> 
>   -- Howard.
> 
> On 30 November 2016 at 09:28, Greg Parker via swift-users <swift-users at swift.org> wrote:
> 
> > On Nov 29, 2016, at 2:55 AM, Rick Mann via swift-users <swift-users at swift.org> wrote:
> >
> > Working on dimensional analysis, I have some proof-of-concept code that seems to be working:
> >
> >    let n1 = kilogram * meter / second * second
> >    ([(kg⋅m) / s]⋅s)
> >
> >     let n2 = kilogram * meter / (second * second)
> >    [(kg⋅m) / (s⋅s)]
> >
> > Note: () around unit products, [] around unit quotients.
> >
> > I'd like to adjust the precedence of operator * for my Unit protocol to be higher than /. Is that possible? It wasn't at all clear to me how to do that in Swift 3, or if can even be done at all.
> 
> You can't. A Swift operator's precedence is the same for all types that implement that operator. Operators * and / cannot use the same precedence on Int but different precedence on Unit.
> 
> You could try to change the precedence of * and / globally - they're defined like any other operator in stdlib/public/core/Policy.swift - but you'll break lots of other code that way.
> 
> 
> --
> Greg Parker     gparker at apple.com     Runtime Wrangler
> 
> 
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-- 
Rick Mann
rmann at latencyzero.com