[swift-users] Attempting to call default protocol implementation crashes Playground
Dan Loewenherz
dan at lionheartsw.com
Tue Nov 15 16:47:58 CST 2016
What are you trying to accomplish here, more concretely?
My first thought is that you shouldn't implement the same function in both
a protocol extension and a conforming class. Why not just give them
different names and call the function from within the extension instead of
from the class? E.g.
protocol FooPro {
func _fooFunc()
}
extension FooPro {
func fooFunc() {
print("fooFunc default")
_fooFunc()
}
}
class FooClass: FooPro {
func _fooFunc() {
print("fooFunc FooClass")
}
}
let fc = FooClass()
fc.fooFunc()
Dan
On Tue, Nov 15, 2016 at 4:28 PM, Rick Mann via swift-users <
swift-users at swift.org> wrote:
> The following gives Xcode 8.1 a very hard time. Eventually I get a Bad
> Access on the last line. I'm guessing it's a recursive call. Is there any
> way to call the default implementation from a "real" implementation?
>
> protocol FooPro
> {
> func fooFunc()
> }
>
> extension FooPro
> {
> func
> fooFunc()
> {
> print("fooFunc default")
> }
> }
>
> class FooClass : FooPro
> {
> func
> fooFunc()
> {
> (self as FooPro).fooFunc()
> print("fooFunc FooClass")
> }
> }
>
> let fc: FooPro = FooClass()
> fc.fooFunc()
>
>
> Thanks!
>
>
> --
> Rick Mann
> rmann at latencyzero.com
>
>
> _______________________________________________
> swift-users mailing list
> swift-users at swift.org
> https://lists.swift.org/mailman/listinfo/swift-users
>
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