[swift-users] Lazy expression is ambiguous?

[Rick Mann]

> On Sep 12, 2016, at 00:53 , Quinn The Eskimo! via swift-users <swift-users at swift.org> wrote:
> 
> 
> On 12 Sep 2016, at 08:46, Rick Mann <rmann at latencyzero.com> wrote:
> 
>> I had assumed lazy worked like static, which I understand uses dispatch_once under the hood.
> 
> Correct.
> 
> [I’m not sure if it actually /uses/ `dispatch_once` specifically, but it has the same semantics.]
> 
>> Would that be a reasonable thing for lazy to do?
> 
> It certainly would be nice.  I suspect that this would be hard to implement because the restrictions associated with `dispatch_once` are pretty tight.  OTOH, if you’d like to see it work this way it wouldn’t hurt to file an enhancement request.

Oh, right, because it seems to need a static or global variable for the flag. I've always wondered why that was the case. Seems like any flag would do (like a member variable), and if that results in a second dispatch because it's a second flag, that's okay.

In any case, thanks for all the clarification.

> 
> Share and Enjoy
> --
> Quinn "The Eskimo!"                    <http://www.apple.com/developer/>
> Apple Developer Relations, Developer Technical Support, Core OS/Hardware
> 
> 
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-- 
Rick Mann
rmann at latencyzero.com