[swift-users] Lazy expression is ambiguous?

[Zhao Xin]

It is not a bug. You must explicitly specify the variable's type if you use
`lazy` keyword. `lazy` means the variable will be initialized later, but
the compiler needs its type right now.

Zhaoxin

On Mon, Sep 12, 2016 at 3:02 PM, Quinn "The Eskimo!" via swift-users <
swift-users at swift.org> wrote:

>
> On 12 Sep 2016, at 06:40, Jacob Bandes-Storch via swift-users <
> swift-users at swift.org> wrote:
>
> > I'd recommend filing a bug at bugs.swift.org.
>
> Agreed.
>
> Also, you can work around this by adding a type.
>
>   lazy var myQ: DispatchQueue = DispatchQueue(label: "Op", attributes:
> .concurrent)
>
> Also, with regards this specific example, be aware that lazy properties
> aren’t guaranteed to be initialised only once.  To quote “The Swift
> Programming Language”:
>
>     If a property marked with the `lazy` modified is accessed by multiple
>     threads simultaneously and the property has not yet been initialized,
>     there is no guarantee that the property will be initialized only once.
>
> I’m struggling to think of a case where that limitation is acceptable in
> the context of a dispatch queue (-:
>
> Share and Enjoy
> --
> Quinn "The Eskimo!"                    <http://www.apple.com/developer/>
> Apple Developer Relations, Developer Technical Support, Core OS/Hardware
>
>
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>
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