[swift-users] Why there's no Character literals?

James Campbell james at supmenow.com
Mon Jul 11 03:53:25 CDT 2016


In Ruby they have special literals, like so:

So this would be an array of chars
%c{a b c d e f g}

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On 11 July 2016 at 05:56, Saagar Jha via swift-users <swift-users at swift.org>
wrote:

> Yes, but then a similar complaint could be made that I *wanted* a String
> this time. The only real way to tell the difference is to use something
> like single quotes.
>
> On Jul 10, 2016, at 14:03, Rick Mann via swift-users <
> swift-users at swift.org> wrote:
>
>
> On Jul 10, 2016, at 11:44 , Saagar Jha via swift-users <
> swift-users at swift.org> wrote:
>
> Well, what if you wanted to create a String with one character? There’s no
> way to differentiate.
>
>
> That hardly seems like the justification. In that case, you'd specify the
> type:
>
>    let s: String = '\n'
>
>
>
> On Jul 7, 2016, at 02:35, 王 黎明 via swift-users [swift-users at swift.org](
> mailto:swift-users at swift.org <swift-users at swift.org>) wrote: >
>
>
> In Swift, we must specify the type for Character variables(because there’s
> no Character literals):
>
> let eol: Character = “\n”
>
> it's not a big problem, but, Is it the unique case that can’t use type
> infer?
>
> swift-users mailing list swift-users at swift.org
> https://lists.swift.org/mailman/listinfo/swift-users
>
> --
> -Saagar Jha
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>
>
> --
> Rick Mann
> rmann at latencyzero.com
>
>
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