[swift-users] Default value for throwing closure argument of a rethrowing function

[Joe Groff]

> On May 16, 2016, at 2:35 AM, bhargav gurlanka via swift-users <swift-users at swift.org> wrote:
> 
> Hi all,
> 
> Could someone please tell me why the following fails?
> 
> func foo(f: () throws -> () = {}) rethrows {
>     try f()
> }
> 
> // Fine
> foo({ })
> 
> // This fails with error:
> //    call is to 'rethrows' function,
> //    but a defaulted argument function can throw
> foo()
> 
> Why should I have to write "try foo()", shouldn't it take the default value (non throwing closure)?

This looks like a bug. We'd appreciate a bug report on bugs.swift.org if you have some time.

-Joe