<div dir="ltr">Just as note, i think the sintax should be:</div><span>
</span><p dir="ltr">0...9<br>
0..<9<br>
0>..9<br>
0>.<9</p><span>
</span><p dir="ltr">Because the intention is produce a number bigger than 0 (start). So<span style="font-size:13px"> greater than zero less than nine.</span></p><div><br></div><div><br></div><div><span>
</span><br><div class="gmail_quote"><div dir="ltr">Em sex, 8 de abr de 2016 22:50, Michel Fortin via swift-evolution <<a href="mailto:swift-evolution@swift.org" target="_blank">swift-evolution@swift.org</a>> escreveu:<br></div><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">Le 8 avr. 2016 à 14:37, Erica Sadun via swift-evolution <<a href="mailto:swift-evolution@swift.org" target="_blank">swift-evolution@swift.org</a>> a écrit :<br>
><br>
> (0 ... 9).striding(by: -2) == [9, 7, 5, 3, 1]<br>
<br>
The above reads wrong to me. The expression has to be read differently depending on the tinny detail that is the sign of the step that comes last:<br>
<br>
* positive step: from 0 to 9 striding by 2<br>
* negative step: to 0 from 9 striding by -2<br>
<br>
Am I the only one thinking it's a bit too clever to swap the start and stop parts like this?<br>
<br>
--<br>
Michel Fortin<br>
<a href="https://michelf.ca" rel="noreferrer" target="_blank">https://michelf.ca</a><br>
<br>
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</blockquote></div></div>