<html><head><meta http-equiv="Content-Type" content="text/html charset=utf-8"></head><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space;" class=""><div><br class=""><blockquote type="cite" class=""><div class=""><div class="" style="font-family: Helvetica; font-size: 12px; font-style: normal; font-variant: normal; font-weight: normal; letter-spacing: normal; orphans: auto; text-align: start; text-indent: 0px; text-transform: none; white-space: normal; widows: auto; word-spacing: 0px; -webkit-text-stroke-width: 0px;">I started poking around. It looks like the rules for calls with functions are different from those with operators. At least in the following example, the operator version doesn't need the &. Any idea why?</div></div></blockquote></div>Seems I'm to late with the answer — but at least my theory was right:<div class="">Assignment-operators would look ugly (imagine all those "inout x = y" ;-)</div><div class=""><br class=""></div><div class="">For me, it would be ok if inout parameters had no special syntax at all — afaik, "&" is just a hint for the possible mutation which could be highlighted typographically (but I'm rather fearless and trust in methods I'm calling :)</div><div class=""><br class=""></div><div class="">Summary:</div><div class="">-1</div><div class=""><br class=""></div><div class="">Tino</div></body></html>