[swift-evolution] Refining SE-0185: Should providing a custom == suppress the default hashValue?
Howard Lovatt
howard.lovatt at gmail.com
Fri Dec 15 13:39:11 CST 2017
+1
I think the simple solution of if you provide either == or hashValue you have to provide both is the best approach. Good catch of this bug.
-- Howard.
> On 16 Dec 2017, at 6:24 am, Daniel Duan via swift-evolution <swift-evolution at swift.org> wrote:
>
> +1. The proposal wasn’t explicit enough to have either supported or be against this IMO. It’s a sensible thing to spell out.
>
> Daniel Duan
> Sent from my iPhone
>
>> On Dec 15, 2017, at 9:58 AM, Joe Groff via swift-evolution <swift-evolution at swift.org> wrote:
>>
>> SE-0185 is awesome, and brings the long-awaited ability for the compiler to provide a default implementation of `==` and `hashValue` when you don't provide one yourself. Doug and I were talking the other day and thought of a potential pitfall: what should happen if you provide a manual implementation of `==` without also manually writing your own `hashValue`? It's highly likely that the default implementation of `hashValue` will be inconsistent with `==` and therefore invalid in a situation like this:
>>
>> struct Foo: Hashable {
>> // This property is "part of the value"
>> var involvedInEquality: Int
>> // This property isn't; maybe it's a cache or something like that
>> var notInvolvedInEquality: Int
>>
>> static func ==(a: Foo, b: Foo) -> Bool {
>> return a.involvedInEquality == b.involvedInEquality
>> }
>> }
>>
>> As currently implemented, the compiler will still give `Foo` the default hashValue implementation, which will use both of `Foo`'s properties to compute the hash, even though `==` only tests one. This could be potentially dangerous. Should we suppress the default hashValue derivation when an explicit == implementation is provided?
>>
>> -Joe
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