[swift-evolution] Optional Argument Chaining

Slava Pestov spestov at apple.com
Mon Dec 11 16:42:46 CST 2017



> On Dec 11, 2017, at 2:41 PM, Jared Khan via swift-evolution <swift-evolution at swift.org> wrote:
> 
> I missed the previous threads! I’ve found one of the relevant threads here:
> https://lists.swift.org/pipermail/swift-evolution/Week-of-Mon-20160711/024201.html <https://lists.swift.org/pipermail/swift-evolution/Week-of-Mon-20160711/024201.html>
> 
> Thanks for this important point.
> 
> If you were to write this logic out by hand then you would short-circuit it and this is analogous to current chaining behaviour so to me evaluating left to right (as Swift usually does) and stopping at the first failed unwrap would make sense. I wouldn’t necessarily say it’s intuitive but I don’t think it’s really less intuitive than the current chaining behaviour. 

I think it gets confusing when you have multiple levels of nested expressions, eg

foo(bar(x?)) + y?

Slava

> 
> Jared
> 
>> On 11 Dec 2017, at 19:28, Xiaodi Wu via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>> 
>> This topic has been discussed at least two and maybe more times in the past.. It’s hard for me to post links at the moment, but it should be possible to find on Google.
>> 
>> One major challenge to this idea, for which no satisfactory answer has been achieved after all these years, is the following issue:
>> 
>> f(g()?, h()?, i(), j()?)?
>> 
>> If g() evaluates to nil, is h() called or not? How about i(), which is not failable? Since any function or property access can have side effects, in what order are the arguments evaluated, and how does one reason about this code flow?
>> 
>> To my mind, in the absence of an intuitive answer to the above—which does not appear to be possible—this idea is not feasible.
>> On Mon, Dec 11, 2017 at 12:34 Magnus Ahltorp via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>> 
>> > 12 Dec. 2017 02:58 Jared Khan <jaredkhan at me.com <mailto:jaredkhan at me.com>> wrote:
>> >
>> > 2. It felt natural to me. It’s analogous to the existing optional chaining scenarios and composes nicely. I think it’s about as understandable as existing chaining, a newbie would have to look it up to discover its meaning. What are your thoughts on this particular syntax (ignoring 3. momentarily)? Hopefully others in this thread can share their views too.
>> 
>> Chaining methods is linear, while nesting fills a similar purpose when we use function calls. This of course affects the way existing Swift code is written, but that is something we have to live with if we want to use familiar syntax patterns. However, I think we have to consider this difference in this case, since the syntax becomes more convoluted. Your suggestion is definitely not as easy to read as the optional chaining syntax, and maybe it can't be.
>> 
>> > As for how common I’d expect it to be, it’s something I’ve run into myself a few times. Again, I hope members of this list can give their view on if this would be useful to them.
>> 
>> I don't have any real examples, but I certainly think that I have run into it, so I'm quite open to solving the problem. For me, it is probably only a matter of finding a syntax that is acceptable.
>> 
>> > 3. I’m not entirely sure what the grammar situation is yet but afaik ‘?’ has never been available as a postfix operator. Perhaps I’m missing your point, could you demonstrate where it is allowed?
>> 
>> I did not expect that you would be able to answer that, it was more a question directed to people who are more connected to the inner workings of the parsing of Swift than I am. It is not allowed, but the error message is not the one I expect, something that gives me a hint that it does have some meaning early in the parsing.
>> 
>> /Magnus
>> 
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