[swift-evolution] [Pitch] Small bit of sugar for enum case with Void associated value

David Sweeris davesweeris at mac.com
Tue Jul 25 15:26:41 CDT 2017

> On Jul 25, 2017, at 12:38, Robert Bennett via swift-evolution <swift-evolution at swift.org> wrote:
> Currently if you have the following enum:
> enum E<T> {
> 	case c(T)
> }
> then if T is Void, you have to write one of the following:
> let x: E<Void> = .c(Void())
> let y: E<Void> = .c(())
> Looks awkward, no? In this case you can omit `<Void>` after `E` because it can be inferred, but if writing a (non-generic) function taking an argument of type `E<Void>`, then the `<Void>` cannot be omitted, and you still have to write `.c(())` for the case name.
> Iā€™m proposing that for enum cases with a single associated value of Void type, or of a generic type that is equal to Void in some instance, you may omit the parentheses altogether and merely write
> let x: E<Void> = .c
> The rationale is twofold: first, double parentheses just looks bad; second, there is only a single value of type Void, which means the associated value of `.c` is trivially inferable, and hence should be omissible.
> I am not proposing that a bare `E.c` imply a type of `E<Void>` ā€” `E.c` should still be illegal in the absence of specification of the generic type ā€” only that when the type is known to be `E<Void>`, `.c` can replace `.c(())`.
> Thoughts?

My first response is +1

My second response is to ask just how much would it break things to expand this and allow omitting the argument anywhere its type is known to be Void? Maybe by implicitly providing a default value of `()` wherever there's a `Void` argument? Like make `func foo(x: Void) {...}` implicitly become `func foo(x: Void = ()) {...}`? I have a sneaking suspicion that this question's already been asked, but I'm not sure.

- Dave Sweeris
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