[swift-evolution] Proposal: Always flatten the single element tuple
Susan Cheng
susan.doggie at gmail.com
Wed Jun 7 22:57:43 CDT 2017
if it's necessary to distinct argument list and tuple, what about the enum?
enum Foo {
case tuple(((((a: Int, b: Int)))))
}
let tuple = Foo.tuple((1, 2))
if case let .tuple(a, b) = tuple {
(a, b) // (1, 2)
}
if case let .tuple(tuple) = tuple {
tuple // (1, 2)
}
2017-06-08 11:36 GMT+08:00 Xiaodi Wu <xiaodi.wu at gmail.com>:
> On Wed, Jun 7, 2017 at 10:15 PM, Susan Cheng via swift-evolution <
> swift-evolution at swift.org> wrote:
>
>> Just a thought
>>
>> if parentheses is important, why the tuples are not?
>>
>
> It is not parentheses that are important; it is the distinction between an
> argument list and a tuple. They both happen to be written with parentheses.
>
> var tuple1: (Int, Int) = (0, 0)
>>
>> var tuple2: ((((Int, Int)))) = (0, 0)
>>
>>
>> type(of: tuple1) == type(of: tuple2) // true
>>
>>
>> var void: ((((((())))))) = ()
>>
>>
>> type(of: void) == type(of: Void()) // true
>>
>>
>> 2017-06-07 10:15 GMT+08:00 Susan Cheng <susan.doggie at gmail.com>:
>>
>>> Introduction
>>>
>>> Because the painful of SE-0110, here is a proposal to clarify the tuple
>>> syntax.
>>>
>>> Proposed solution
>>> 1. single element tuple always be flattened
>>>
>>> let tuple1: (((Int))) = 0 // TypeOf(tuple1) == Int
>>>
>>>
>>> let tuple2: ((((Int))), Int) = (0, 0) // TypeOf(tuple2) == (Int, Int)
>>>
>>> 2. function arguments list also consider as a tuple, which means the
>>> function that accept a single tuple should always be flattened.
>>>
>>> let fn1: (Int, Int) -> Void = { _, _ in }
>>>
>>>
>>> let fn2: ((Int, Int)) -> Void = { _, _ in } // always flattened
>>>
>>> let fn3: (Int, Int) -> Void = { _ in } // not allowed, here are two
>>> arguments
>>>
>>> let fn4: ((Int, Int)) -> Void = { _ in } // not allowed, here are two
>>> arguments
>>>
>>>
>>
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>>
>>
>
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