# [swift-evolution] [Proposal][Discussion] Deprecate Tuple Shuffles

Rien Rien at Balancingrock.nl
Fri May 5 01:39:07 CDT 2017

```I think your misunderstanding helped a lot of people understand what is at issue here :-)

It did for me!

+1

Regards,
Rien

Site: http://balancingrock.nl
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> On 05 May 2017, at 08:33, Adrian Zubarev via swift-evolution <swift-evolution at swift.org> wrote:
>
> I’m aware what a label is, I just had a small misunderstanding about nested destructuring. ;-)
>
> Issue solved for me.
>
> let (a, b /* inner tuple */) = tuple
>
> let (_, (x, y)) = tuple
>
> +1 I don’t mind this change at all.
>
>
>
>
> --
> Sent with Airmail
>
> Am 5. Mai 2017 um 08:14:10, Xiaodi Wu (xiaodi.wu at gmail.com) schrieb:
>
>> On Fri, May 5, 2017 at 1:12 AM, Adrian Zubarev <adrian.zubarev at devandartist.com> wrote:
>> Oh pardon, on the first glance I didn’t realized the issue with that example.
>>
>> Here is an updated example that would work:
>>
>> let (first, second: (x, y)): (first: Int, second: (x: Int, y: Int)) = tuple
>>
>> This should work right?
>>
>> No, again, this would be banned. You are using a label (a thing that ends in a colon) inside a tuple pattern (a thing between parenthesis that comes after "let").
>>
>> It’s assigning the inner tuple to second while also creating two additional constants from the inner tuple. I know this is redundant and can be used as second.x, but this should work like right, because it’s nested tuple destructuring? If we’d use var instead of let then x would contain the value assigned from the inner tuple, but it would be completely independent from the new second tuple variable.
>>
>>
>>
>> --
>> Sent with Airmail
>>
>> Am 5. Mai 2017 um 08:04:07, Xiaodi Wu (xiaodi.wu at gmail.com) schrieb:
>>
>>> let (first: a, second: (x: b, y: c)): (first: Int, second: (x: Int, y: Int)) = tuple // fine, unaffected
>>> This would be banned. You are using labels (things ending with a colon) in a pattern (the stuff that comes after the word "let").
>>
>
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