[swift-evolution] [Idea] Generic associated types
Austin Zheng
austinzheng at gmail.com
Sat Mar 11 23:51:12 CST 2017
I think you want higher-kinded types. https://github.com/apple/swift/blob/master/docs/GenericsManifesto.md#higher-kinded-types <https://github.com/apple/swift/blob/master/docs/GenericsManifesto.md#higher-kinded-types>
Best,
Austin
> On Mar 11, 2017, at 9:49 PM, Karl Wagner via swift-evolution <swift-evolution at swift.org> wrote:
>
> I have a model like this:
>
> protocol Promise {
> associatedtype Result
> }
>
> protocol Scanner {
> associatedtype ScanPromise: Promise
>
> func promiseScan<T>(from: Offset, until: (Offset, Item) -> T?) -> ScanPromise // where Result == T?
> }
>
> The thing that I’m trying to express is: whichever type implements the associated type ‘ScanPromise’ must be generic, and that parameter must be its result (i.e. something it got as a result of calling the “until” closure).
>
> Even with SE-0142, this kind of constraint would not be possible. What I would like to write is something like this:
>
> protocol Promise {
> associatedtype Result
> }
>
> protocol Scanner {
> associatedtype ScanPromise<T>: Promise // now generic. [SE-0142]: where Result == T
>
> func promiseScan<T>(from: Offset, until: (Offset, Item) -> T?) -> ScanPromise<T>
> }
>
> Thoughts?
>
> - Karl
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