[swift-evolution] Infer types of default function parameters

Jaden Geller jaden.geller at gmail.com
Sat Mar 11 19:09:47 CST 2017


Ahh, misunderstanding then. I had thought they were suggesting this was the default value of the typealias.

Thanks for clearing that up,
Jaden Geller

> On Mar 11, 2017, at 5:08 PM, Robert Widmann <devteam.codafi at gmail.com> wrote:
> 
> You may be missing/misspelling the typealias declaration.  This has been in Policy.swift for a while now, and I can reproduce this as far back as 2.2 in the Bluemix sandbox.
> 
> ~Robert Widmann
> 
>> On Mar 11, 2017, at 7:41 PM, Jaden Geller via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>> 
>> 
>>> On Mar 11, 2017, at 3:22 PM, Ben Cohen <ben_cohen at apple.com <mailto:ben_cohen at apple.com>> wrote:
>>> 
>>>> 
>>>> On Mar 11, 2017, at 1:17 PM, Jaden Geller via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>>>> 
>>>> 
>>>> 
>>>> On Mar 11, 2017, at 12:20 PM, David Sweeris via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>>>> 
>>>>> 
>>>>>> On Mar 11, 2017, at 12:57 AM, Jean-Daniel via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>>>>>> 
>>>>>> -1
>>>>>> 
>>>>>> It would be inconsistent to allow it for deterministic literals (String) and not for non deterministic literal (int which can be either a Int, Uint, Float, …)
>>>>> 
>>>>> If I’m not mistaken, even with `bar = “baz”`, `String` is merely the default inferred type. It could be anything that conforms to `ExpressibleByStringLiteral`, right? In that regard, this is kinda just a way to make a function implicitly generic:
>>>>> func foo(bar = "baz") {…}
>>>>> becomes:
>>>>> func foo<T: ExpressibleByStringLiteral>(bar: T = "baz") {…}
>>>>> 
>>>> 
>>>> As I understood it, omitting the type would work identically to `let` declarations. A string literal without a type defaults to `String`. Treating it as a generic function is a bad idea IMO.
>>>> 
>>> 
>>> More specifically, a string literal without a type defaults to the StringLiteralType typealias:
>>> 
>>> typealias StringLiteralType = StaticString
>>> let s = "abc"
>>> print(type(of: s))
>>> // prints StaticString
>> 
>> What version of the Swift compiler are you using? I don’t observe this behavior. That code prints `String` for me.
>> 
>>> 
>>>> I don't think this sugar is worth any amount of added complexity. Most function arguments will have not have default values and this have to continue to declare the type, so this would only be more concise in very few cases. I'd prefer the consistency of always having to explicitly declare the argument type at a function boundary.
>>>> 
>>>> To call a function, you need to know what type to pass in. This becomes more difficult when not make explicit, particularly when a more complicated expression is used as a default. -1
>>>> 
>>>>> Is there anything we can do with a variable, if all we know of it is that it conforms to `ExpressibleByStringLiteral`? I can’t think of anything… If we had a way to get back the literal string which the variable was initialized with, we could initialize other values with that, but the protocol doesn’t require us to store it. Come to think of it, is there even a way to store a literal value in its “untyped” form? You can declare a variable to of type `IntegerLiteralType`, but the type system then treats it as an `Int`.
>>>>> 
>>>>> So while it looks nice (to me, anyway) I’m not sure you could actually do anything with it. Or am I looking at this wrong?
>>>>> 
>>>>> - Dave Sweeris
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