[swift-evolution] Strings in Swift 4
David Sweeris
davesweeris at mac.com
Tue Jan 31 17:28:41 CST 2017
> On Jan 31, 2017, at 2:04 PM, Xiaodi Wu <xiaodi.wu at gmail.com> wrote:
>
> On Tue, Jan 31, 2017 at 3:36 PM, David Sweeris via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>
> On Jan 31, 2017, at 11:32, Jaden Geller via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>
>> I think that is perfectly reasonable, but then it seems weird to be able to iterate over it (with no upper bound) independently of a collection). It would surprise me if
>> ```
>> for x in arr[arr.startIndex…] { print(x) }
>> ```
>> yielded different results than
>> ```
>> for i in arr.startIndex… { print(arr[i]) } // CRASH
>> ```
>> which it does under this model.
>
> (I think this how it works... semantically, anyway) Since the upper bound isn't specified, it's inferred from the context.
>
> In the first case, the context is as an index into an array, so the upper bound is inferred to be the last valid index.
>
> In the second case, there is no context, so it goes to Int.max. Then, after the "wrong" context has been established, you try to index an array with numbers from the too-large range.
>
> Semantically speaking, they're pretty different operations. Why is it surprising that they have different results?
>
> I must say, I was originally rather fond of `0...` as a spelling, but IMO, Jaden and others have pointed out a real semantic issue.
>
> A range is, to put it simply, the "stuff" between two end points. A "range with no upper bound" _has to be_ one that continues forever. The upper bound _must_ be infinity.
Depends… Swift doesn’t allow partial initializations, and neither the `.endIndex` nor the `.upperBound` properties of a `Range` are optional. From a strictly syntactic PoV, a "Range without an upperBound” can’t exist without getting into undefined behavior territory.
Plus, mathematically speaking, an infinite range would be written "[x, ∞)", with an open upper bracket. If you write “[x, ∞]”, with a closed upper bracket, that’s kind of a meaningless statement. I would argue that if we’re going to represent that “infinite” range, the closest Swift spelling would be “x..<“. That leaves the mathematically undefined notation of “[x, ∞]”, spelled as "x…” in Swift, free to let us have “x…” or “…x” (which by similar reasoning can’t mean "(∞, x]”) return one of these:
enum IncompleteRange<T> {
case upperValue(T)
case lowerValue(T)
}
which we could then pass to the subscript function of a collection to create the actual Range like this:
extension Collection {
subscript(_ ir: IncompleteRange<Index>) -> SubSequence {
switch ir {
case .lowerValue(let lower): return self[lower ..< self.endIndex]
case .upperValue(let upper): return self[self.startIndex ..< upper]
}
}
}
- Dave Sweeris
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