[swift-evolution] [draft] Compound Names For Enum Cases

Daniel Duan daniel at duan.org
Tue Jan 24 16:53:14 CST 2017



Daniel Duan
Sent from my iPhone

> On Jan 24, 2017, at 2:18 PM, Christopher Kornher via swift-evolution <swift-evolution at swift.org> wrote:
> 
> I agree that  this rule would be consistent with the handing of Swift function signatures, but my proposal is self-consistent and:
> 
> 1) It is more powerful, matching on the case name or not as required.
> 2) Is consistent with existing switches that ignore associated values
> 3) Is constant with ignored labels in other Swift constructs (proposed and in past versions of Swift, at least)
> 4) Avoids a possible API change for current enums. This is currently legal but would not be if the enum case “name” is the entire signature for constructing it:
> 
> ```
> enum E {
>     case a( a: Int )
>     case b( a: Int )
> }
> 
> let anEmum = E.a( a: 4 )
> 
> 
> switch anEmum {
> case .a( let x ) :
>     break
> case .b( let x ) :
>     break
> }
> 
> switch anEmum {
> case .a( let y ) :
>     break
>     
> case .b( let y ) :
>     break
> }
> ```
> So is this proposal worth creating a breaking change? I don’t think so.  it would be possible to ignore the associated parameter name, but not the type, but that would further confuse case matching, I believe.
> 
> I personally don’t see much purpose in having two enum cases with the same name if they are always treated as distinct and there is no way to reason on the case name.

Would you say the same for functions? Our opinions differ in what constitute a "name". In Swift, function names include parameters. Each enum case declares a function that creates a enum value. That's why it's *more* consistent for enum to have a similar definition of "name".

As for pattern matching, number of patterns the number of cases being matched have a many-to-one relationships. This is true in Swift and many 

> If they are always distinct, then requiring different names eliminates unnecessary cognitive load. There is a good reason for functions to have the same “name” and different signatures, and there are precedents in many languages. 
> 
> You may disagree, but I believe that enums exist to support reasoning on distinct cases and that muddying that by treating the associated value as part of the “signature" increases the language “surface area” while adding no tangible benefit.
> 
> 
>>> On Jan 24, 2017, at 2:23 PM, Matthew Johnson via swift-evolution <swift-evolution at swift.org> wrote:
>>> 
>>> 
>>> On Jan 24, 2017, at 3:10 PM, Christopher Kornher via swift-evolution <swift-evolution at swift.org> wrote:
>>> 
>>> Your example is only has only one case, which is not typical. Perhaps I am missing something, but the only reason that I can imagine for having a case with multiple ways to “construct” it is to have all variants of the case to match. If you don’t want them to match, use a different case name. 
>> 
>> It sounds like you are missing something.  The `bar(a:)` and `bar(b:)` are the full case names.  These are *not* the same case.  The `bar` shorthand is allowed when there is no ambiguity, however for an enum with both `bar(a:)` and `bar(b:)` there *is* ambiguity and therefore the `bar` shorthand is not allowed.  The programmer is required to spell out the full name of the case they wish to match.
>> 
>> 
>>> 
>>> It would still be possible to match on the different types of bar when needed:
>>> 
>>> ```
>>> enum Foo {
>>>     case bar(a: Int)
>>>     case bar(b: String)
>>>     case notAbar
>>> }
>>> 
>>> 
>>>  switch aFoo {
>>>     case .bar( let a: Int) : // matches Ints only 
>>> 	...
>>> 
>>>     case .bar( let b: String) : // matches Strings only
>>>        ...
>>> }
>>> 
>>> switch aFoo {
>>>     case .bar :  // Matches both  cases and that is a good thing
>>>>>> 
>>>     case notAbar:
>>> 	….
>>> }
>>> 
>>> ```
>>> 
>>>> On Jan 24, 2017, at 5:27 AM, Xiaodi Wu via swift-evolution <swift-evolution at swift.org> wrote:
>>>> 
>>>> I would imagine it would be logical to have it work just like it does now with functions. If case bar is distinct, then that should still work, but if bar is "overloaded," then case bar should be invalid for ambiguity. Seems fine to me, shouldn't break any existing code and therefore we don't lose anything.
>>>> 
>>>> 
>>>>> On Tue, Jan 24, 2017 at 01:13 David Hart via swift-evolution <swift-evolution at swift.org> wrote:
>>>>> 
>>>>> 
>>>>>> On 24 Jan 2017, at 00:52, Joe Groff via swift-evolution <swift-evolution at swift.org> wrote:
>>>>>> 
>>>>>> We're not terribly principled about this right now with non-pattern declaration references. You can still reference an unapplied function by its base name alone without its labels, if it's unambiguous:
>>>>>> 
>>>>>> func foo(x: Int, y: Int) {}
>>>>>> 
>>>>>> let foo_x_y: (Int, Int) -> () = foo
>>>>>> 
>>>>>> so it'd be consistent to continue to allow the same in pattern references.
>>>>> 
>>>>> WRT ambiguity, do we loose the ability to pattern match on the naked case name when two cases share the same base name?
>>>>> 
>>>>> enum Foo {
>>>>>     case bar(a: Int)
>>>>>     case bar(b: String)
>>>>> }
>>>>> 
>>>>> switch aFoo {
>>>>>     case .bar: // matches both cases
>>>>>         break
>>>>> }
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