[swift-evolution] [Pitch] inout with capture variable

Cao Jiannan frogcjn at 163.com
Thu Oct 6 00:07:39 CDT 2016


so if developer want to capture an variable inference, must declare a new variable.

class A {
    var value = 1
    
    func test() -> () -> Int {
        var capturedValue = self.value
        let editInfo = { () -> Int in 
            capturedValue += 1
            return capturedValue
        }
        return editInfo
    }
}

let a = A()

let editInfo = a.test()
print(editInfo()) // 2
print(a.value) // 1
print(editInfo()) // 3
print(a.value) // 1

what about:

class A {
    var value = 1
    
    func test() -> () -> Int {
        let editInfo = { [inout value] () -> Int in 
            capturedValue += 1
            return capturedValue
        }
        return editInfo
    }
}

let a = A()

let editInfo = a.test()
print(editInfo()) // 2
print(a.value) // 2
print(editInfo()) // 3
print(a.value) // 3

> > On Oct 5, 2016, at 9:06 PM, Cao Jiannan via swift-evolution<swift-evolution at swift.org>wrote:
> > 
> > for example:
> > 
> > var a = 1
> > 
> > let block = { [inout a] in
> > a += 1
> > }
> > 
> > block()
> > block()
> > 
> > print(a) // 3
> This is already how captures work by default in closures and nested functions in Swift:
> 
> var a = 1
> 
> let block = { a += 1 }
> 
> block()
> block()
> 
> print(a) // prints 3
> 
> 
> If you want to capture something immutably you can put it in the capture list:
> 
> var a = 1
> let block = { [a] in a += 1 } // error: left side of mutating operator isn't mutable: 'a' is a 'let' constant
> 
> Mark
> 
> > 
> > 
> > _______________________________________________
> > swift-evolution mailing list
> > swift-evolution at swift.org
> > https://lists.swift.org/mailman/listinfo/swift-evolution
> 
> 
> 
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