[swift-evolution] [Pitch] Refactor Metatypes

[Goffredo Marocchi]

Love it :)!

Sent from my iPhone

> On 2 Oct 2016, at 09:37, Adrian Zubarev via swift-evolution <swift-evolution at swift.org> wrote:
> 
> That’s right. I was about to say something similar about the Of.
> 
> Actually Type<T> would be the correct name for the static/concrete metatype.
> 
> We already have this notation but not in a generic way T.Type
> If we add of only in our mind to Type<T>, we’ll get “Type of a type T” which is shortly referred as a “metatype of T”. (Array<Element> - Array of Element type)
> Since Subtype<T> in reality is some *existential metatype* and the whole talk about existential types now tend to have the Any prefix, lets follow that trend here too.
> 
> Type<T> - (static/concrete/exact) metatype.
> AnyType<T> - existential metatype.
> It might be even easier to memorise this name than Subtype.
> 
> The example from the proposal rewritten:
> 
> // Types:
> protocol Foo {}
> protocol Boo : Foo {}
> class A : Foo {}
> class B : A, Boo {}
> struct S : Foo {}
> 
> // Metatypes:
> let a1: Type<A> = A.self           //=> Okay
> let p1: Type<Foo> = Foo.self       //=> Okay
> let p2: Type<Boo> = C.self         //=> Error -- `C` is not the same as `Foo`
> 
> let any_1: AnyType<Any> = A.self   //=> Okay
> let any_2: AnyType<Any> = Foo.self //=> Okay
> 
> let a_1: AnyType<A> = A.self       //=> Okay
> let p_1: AnyType<Foo> = A.self     //=> Okay
> let p_2: AnyType<Foo> = Foo.self   //=> Error -- `Type<Foo>` is not a subtype of `AnyType<Foo>`
> 
> // Generic functions:
> func dynamic<T>(type: AnyType<Any>, `is` _: Type<T>) -> Bool {
>   return type is AnyType<T>
> }
> 
> func dynamic<T>(type: AnyType<Any>, `as` _: Type<T>) -> AnyType<T>? {
>   return type as? AnyType<T>
> }
> 
> let s1: Type<S> = S.self
> 
> dynamic(type: s1, is: Foo.self)    //=> true
> dynamic(type: s1, as: Foo.self)    //=> an `Optional<AnyType<Foo>>`
> The type(of:) function could now stay, because now we’d only need to change the return type.
> 
> func type<T>(of instance: T) -> AnyType<T>
> Isn’t this a good compromise?
> 
> 
> 
> -- 
> Adrian Zubarev
> Sent with Airmail
> 
> Am 2. Oktober 2016 um 09:01:45, Pyry Jahkola via swift-evolution (swift-evolution at swift.org) schrieb:
> 
>> OTOH, we don't have ArrayOf<Element> or DictionaryOfKeyAndValue<Key, Value>, while we still pronounce them that way. I don't think prepositions belong in the name of types but in exceptional cases, and this doesn't sound exceptional enough to me.
> 
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