[swift-evolution] Passing an optional first argument to sequence(first:next:)
Dave Abrahams
dabrahams at apple.com
Thu Sep 1 17:47:58 CDT 2016
on Mon Aug 29 2016, Tim Vermeulen <swift-evolution at swift.org> wrote:
> The intent of my function wasn’t very clear, but it was supposed to
> return a sequence that contains *all* consecutive pairs, i.e. (0 ..<
> 4).pairs would result in [(0, 1), (1, 2), (2, 3)].
extension Sequence {
typealias Element = Iterator.Element
/// All adjacent pairs of elements, in order.
var allAdjacentPairs: UnfoldSequence<(Element, Element), (i: Iterator, e: Element?)> {
var i = makeIterator()
let e = i.next()
return sequence(state: (i, e)) {
(s: inout (i: Iterator, e: Element?))->(Element, Element)? in
let e = s.i.next()
defer { s.e = e }
return e.map { (s.e!, $0) }
}
}
}
for j in 0..<10 {
print(Array((0..<j).allAdjacentPairs))
}
--
-Dave
More information about the swift-evolution
mailing list