[swift-evolution] [Idea] Use optionals for non-optional parameters

[Charles Srstka]

> On Aug 15, 2016, at 2:27 PM, Xiaodi Wu via swift-evolution <swift-evolution at swift.org> wrote:
> 
> `let value = (x == nil) ? nil : foo.bar(x: x)` isn't so bad, is it? You could even write a custom operator to sugar it.

It’s distasteful, due to the need to use the force-unwrap operator. In cases like this, I usually end up writing:

let value: Foo? = nil

if let x = x {
	value = foo.bar(x: x)
} else {
	value = nil
}

or:

let value: Foo? = {
	if let x = x {
		return foo.bar(x: x)
	} else {
		return nil
	}
}()

Both of which are unwieldy, but necessary to avoid the use of !.

I wouldn’t mind something like an overload on the ternary operator:

let value = x? ? foo.bar(x: x) : nil

in which a ? after the ternary condition indicates that it is an optional to be unwrapped for the positive condition.

Charles

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