[swift-evolution] [Discussion] Breaking precedence

Xiaodi Wu xiaodi.wu at gmail.com
Tue Aug 2 16:55:39 CDT 2016

Well, there I disagree. All of these operations take integers and produce
other integers. As we've discussed, the bitwise operators resemble
multiplication or addition in particular ways; not so different at all.
This is IMO a weak argument because you're arguing gradations of "so
different", which is entirely subjective in the end.

What I'm saying is that I would be mildly in favor of your proposal because
I can justify it on the basis of something black-and-white: conflicting
"levels" at which these operators work on integers (collection of bits vs.
element in the set of all integers) and the concomitant differences
regarding when these operators trap.
On Tue, Aug 2, 2016 at 16:49 Anton Zhilin <antonyzhilin at gmail.com> wrote:

> 2016-08-03 0:46 GMT+03:00 Xiaodi Wu <xiaodi.wu at gmail.com>:
>> It's not that << will overflow and / will not. Substitute * for / and the
>> argument would be the same. The difference is that << traps when you shift
>> more than the total number of bits but does *not* trap when you shift
>> numbers off as would arithmetic exponentiation; * traps on overflow. Thus,
>> what << is concerned about is the bits (as it should), but * is concerned
>> about the max representable value.
> Substitute * for / and my argument would also be the same :)
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