[swift-evolution] Enhanced existential types proposal discussion
laurent.mihalkovic at gmail.com
Mon May 30 10:56:18 CDT 2016
> On May 30, 2016, at 5:22 AM, Charles Srstka via swift-evolution <swift-evolution at swift.org> wrote:
>> On May 29, 2016, at 10:13 PM, Matthew Johnson <matthew at anandabits.com <mailto:matthew at anandabits.com>> wrote:
>> On May 29, 2016, at 9:43 PM, Charles Srstka <cocoadev at charlessoft.com <mailto:cocoadev at charlessoft.com>> wrote:
>>>> On May 29, 2016, at 9:20 PM, Matthew Johnson <matthew at anandabits.com <mailto:matthew at anandabits.com>> wrote:
>>>> On May 29, 2016, at 5:43 PM, Charles Srstka via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>>>>>> On May 29, 2016, at 5:16 PM, Austin Zheng <austinzheng at gmail.com <mailto:austinzheng at gmail.com>> wrote:
>>>>>> I think the problem here is that P == P is true, but P : P is not (a protocol does not conform to itself).
not that simple. see further down.
>>>>> But if you have a variable, parameter, etc. typed as P, that’s *not* the protocol, since protocols aren’t concrete entities. What you have there, by definition, is something that conforms to P. Similarly, something like [P] is just a collection of things, perhaps of various types, which all have the common feature that they conform to P.
>>>> You have an existential value of type P. It is a well known frustration in Swift that the existential type corresponding to a protocol does not conform to the protocol. This has been discussed off and on at different times.
>>>> There are a couple of reasons this is the case. IIRC in some cases it actually isn't possible for the existential to conform to the protocol in a sound way. And even when it is possible, I believe it has been said that it is more difficult to implement than you might think. Hopefully the situation will improve in the future but I'm not aware of any specific plans at the moment.
>>> It’s been my understanding that a variable typed P in swift is equivalent to what we would have called id <P> in Objective-C—that is, an object of unknown type that conforms to P. Is this not the case? I am curious what the conceptual difference would be, as well as the rationale behind it.
>> Existentials have their own type in Swift. The problem you are running into is because the generic constraint is looking at the existential type of P and asking if that type conforms to P (which it does not - you can't write the conformance and the compiler does not provide it for you). It is not asking if the type of the object underlying the existential value conforms to P (which it necessarily does). When you have a value of type P you have already erased the type of the underlying object.
> Have we not also erased the type of the underlying object with id <P>, though? The only thing we get from the “id” is that it’s an Objective-C object of some type, which it would have to have been anyway in order to conform to the protocol in the first place. Thus the type of the object is erased, and the only thing we know about it is that it conforms to the protocol—just like something typed P in Swift.
> What I’m trying to figure out is whether there’s any positive benefit or rationale to the reason things work the way they do here, or whether it’s just bugs / implementation details.
I’ve been wondering about that one because of this:
/// Whether the existential of this protocol conforms to itself.
unsigned ExistentialConformsToSelf : 1;
but in the end it is false for non obj-c protocols (which eliminates the Struct in the example). but there are still more rules
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