[swift-evolution] Proposal: Deprecate optionals in string interpolation

Dan Appel dan.appel00 at gmail.com
Thu May 19 23:48:34 CDT 2016


>google for swift print optional stackoverflow. I think that kind of speaks
for itself.

I think this is actually an example of why the current behavior is a
*good* thing.
I did just google that and the top comment of the first result explains
what an optional is. That is very good and encourages beginners to
understand how optionals work under the hood. If you hide that from them,
they will only be even more confused when they see just the string "nil"
pop up when it previously was showing the correct value.

On Thu, May 19, 2016 at 9:36 PM Krystof Vasa via swift-evolution <
swift-evolution at swift.org> wrote:

> BTW - google for swift print optional stackoverflow. I think that kind of
> speaks for itself.
>
> > On May 19, 2016, at 6:07 PM, Jeremy Pereira via swift-evolution <
> swift-evolution at swift.org> wrote:
> >
> > -1
> >
> > This seems to me like crippling string interpolation just because
> sometimes we make mistakes. 99% of the time, if I interpolate an optional,
> it’s because I want it that way. I don’t want to have to put up with a
> warning or write the same boilerplate 99% of the time just to flag up the
> 1% more easily. Sorry.
> >
> >> On 18 May 2016, at 19:50, Krystof Vasa via swift-evolution <
> swift-evolution at swift.org> wrote:
> >>
> >> The string interpolation is one of the strong sides of Swift, but also
> one of its weaknesses.
> >>
> >> It has happened to me more than once that I've used the interpolation
> with an optional by mistake and the result is then far from the expected
> result.
> >>
> >> This happened mostly before Swift 2.0's guard expression, but has
> happened since as well.
> >>
> >> The user will seldomly want to really get the output
> "Optional(something)", but is almost always expecting just "something". I
> believe this should be addressed by a warning to force the user to check
> the expression to prevent unwanted results. If you indeed want the output
> of an optional, it's almost always better to use the ?? operator and supply
> a null value placeholder, e.g. "\(myOptional ?? "<<none>>")", or use
> myOptional.debugDescription - which is a valid expression that will always
> return a non-optional value to force the current behavior.
> >>
> >> Krystof
> >>
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> >
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-- 
Dan Appel
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