[swift-evolution] Protocol non-conformance clause
Erica Sadun
erica at ericasadun.com
Fri Apr 29 10:20:27 CDT 2016
In Wux's example, he has third party code:
```
Type ThirdParty {
func foo() { print("from third party") }
}
```
Then in his own code, he defines protocol A and extends it:
extension A {
func foo() {
print("Self is B")
}
}
and conforms ThirdParty to A. But he wants the original foo() implementation. Your approach
for writing an extension for plain A without a where clause doesn't offer that solution. The goal
here is "Add this default behavior *only* where a type does not conform to B"
-- E
> On Apr 29, 2016, at 9:10 AM, Thorsten Seitz <tseitz42 at icloud.com> wrote:
>
> Just writing an extension for plain A without a where clause works.
>
> -Thorsten
>
> Am 29.04.2016 um 16:03 schrieb Erica Sadun via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>>:
>
>> Gmane is down as far as my browser is concerned and I haven't found anything by Googling.
>>
>> Given the following:
>>
>> protocol A {func foo()}
>> protocol B {} // empty protocol
>>
>> extension A where Self:B {
>> func foo() {
>> print("Self is B")
>> }
>> }
>>
>> // Works
>> struct S1: A, B {}
>> S1().foo()
>>
>> Is there a way to produce a similar extension that exempts any type that conforms to B?
>>
>> cc'ing in Wux because this is a direct response to a scenario he brought up yesterday.
>>
>> -- E
>>
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>> swift-evolution at swift.org <mailto:swift-evolution at swift.org>
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