[swift-evolution] Feature proposal: Range operator with step
Stephen Canon
scanon at apple.com
Wed Apr 6 16:26:37 CDT 2016
> On Apr 6, 2016, at 2:25 PM, Dave Abrahams via swift-evolution <swift-evolution at swift.org> wrote:
>
>
> on Wed Apr 06 2016, Erica Sadun <erica-AT-ericasadun.com> wrote:
>
>> On Apr 6, 2016, at 3:05 PM, Dave Abrahams via swift-evolution
>> <swift-evolution at swift.org> wrote:
>>
>> on Wed Apr 06 2016, Xiaodi Wu <xiaodi.wu-AT-gmail.com> wrote:
>>
>> On Wed, Apr 6, 2016 at 3:28 PM, Dave Abrahams via swift-evolution
>> <swift-evolution at swift.org> wrote:
>>
>> You if you need to represent `<..` intervals in scientific computing,
>> that's a pretty compelling argument for supporting them.
>>
>> I'd like to be able to represent any of those as
>> Intervals-which-are-now-Ranges. It makes sense to do so because
>> the
>> things I want to do with them, such as clamping and testing if
>> some
>> value is contained, are exactly what Intervals-now-Ranges
>> provide.
>> Looking around, it seems many other languages provide only what
>> Swift
>> currently does, but Perl does provide `..`, `..^`, `^..`, and
>> `^..^`
>> (which, brought over to Swift, would be `...`, `..<`, `<..`, and
>> `<.<`).
>>
>> Do we need fully-open ranges too?
>>
>> I haven't encountered a need for open ranges, but I would expect that
>> other applications in scientific computing could make use of them.
>> I rather like Pyry's suggestions below.
>>
>> Below?
>>
>> Logically in time below.
>
> Oh! In my application, time flows downward.
>
>>
>> I believe the following is a valid conversion of the Xiaodi Wu below into the
>> Dave A domain.
>>
>> On Apr 6, 2016, at 2:29 PM, Pyry Jahkola via swift-evolution
>> <swift-evolution at swift.org> wrote:
>>
>> I think a sensible specification would be that with a positive step size,
>> the count starts from the lower bound, and with a negative one, it starts
>> from the upper bound (inclusive or exclusive). Thus, the following examples
>> should cover all the corner cases:
>>
>> (0 ... 9).striding(by: 2) == [0, 2, 4, 6, 8]
>> (0 ..< 9).striding(by: 2) == [0, 2, 4, 6, 8]
>> (0 <.. 9).striding(by: 2) == [2, 4, 6, 8]
>> (0 <.< 9).striding(by: 2) == [2, 4, 6, 8]
>>
>> (0 ... 9).striding(by: 3) == [0, 3, 6, 9]
>> (0 ..< 9).striding(by: 3) == [0, 3, 6]
>> (0 <.. 9).striding(by: 3) == [3, 6, 9]
>> (0 <.< 9).striding(by: 3) == [3, 6]
>>
>> (0 ... 9).striding(by: -2) == [9, 7, 5, 3, 1]
>> (0 ..< 9).striding(by: -2) == [7, 5, 3, 1]
>> (0 <.. 9).striding(by: -2) == [9, 7, 5, 3, 1]
>> (0 <.< 9).striding(by: -2) == [7, 5, 3, 1]
>>
>> (0 ... 9).striding(by: -3) == [9, 6, 3, 0]
>> (0 ..< 9).striding(by: -3) == [6, 3, 0]
>> (0 <.. 9).striding(by: -3) == [9, 6, 3]
>> (0 <.< 9).striding(by: -3) == [6, 3]
>
> These all look reasonable to me.
Agreed.
– Steve
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