[swift-evolution] Feature proposal: Range operator with step

Erica Sadun erica at ericasadun.com
Mon Mar 28 17:35:30 CDT 2016

> On Mar 28, 2016, at 3:54 PM, Dave Abrahams via swift-evolution <swift-evolution at swift.org> wrote:
> on Mon Mar 28 2016, Erica Sadun <swift-evolution at swift.org> wrote:
>>> On Mar 28, 2016, at 3:25 PM, Dave Abrahams via swift-evolution
>>> <swift-evolution at swift.org> wrote:
>>> on Mon Mar 28 2016, Xiaodi Wu
>>> <swift-evolution at swift.org
>>> <mailto:swift-evolution at swift.org>>
>>> wrote:
>>>> Right, Countable could refine Strideable. I'm no expert on this, but
>>>> some cursory reading suggests that the analogous feature in C++ simply
>>>> requires the type to have operator++ defined. Obviously, that won't
>>>> work for Swift 3.0...
>>> Hmm, instead of defining a new protocol (Countable), what if we just use
>>> “Strideable where Stride : Integer” as a constraint?
>> I like a differentiation between continuous and discrete things
>> although both can have ranges, membership, fences,
>> and a way to stride through them
> Strideable where Stride : Integer expresses just exactly that.  Now if I
> could only get the type-checker to cooperate...

I am ridiculously excited about what you're doing there. 
Looking forward to beautiful floating point strides if for no
other reason than I can point out how well they work for math
in comparison to traditional for;;loops, so maybe people will
stop burning semicolons on my lawn.

What are you feelings about disjoint and invertible intervals? 
(I'll admit they currently fail the Lattner test[1], but they appeal to
my aesthetics)

-- E

[1] First rule of Lattner: A language change should provide a highly focused
tweak to Swift with limited impact and a measurable benefit to developers

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