[swift-evolution] Feature proposal: Range operator with step

Haravikk swift-evolution at haravikk.me
Wed Mar 23 18:02:09 CDT 2016

I’m behind the idea in principle, but I’m not so sure we need a new keyword for this:

	for eachIndex in (1 ..< 10).by(2) { … }

The above would be adequate I thin, and just requires a new method on ranges and similar types. This is being discussed, among other things, in the c-style for loop discussion, as these were recently removed but without a replacement for this type of use-case.

> On 23 Mar 2016, at 21:40, David Knothe via swift-evolution <swift-evolution at swift.org> wrote:
> Hi,
> I am new to Swift mailing list so I don’t know if this topic has already been discussed.
> I like Swift's range operators ..< and …
> What I am missing though is an easy operator to create a range with a specified step. Currently, if you would want to iterate over some odd numbers, you had to write:
> for i in 1.stride(through: 7, by: 2) { … }
> What I think would be simpler and more convenient would be something like the following:
> for i in 1 … 7 step 2 { … } . Another option would be  for i in 1 … 7; 2 { … }
> The keyword ‚step‘ in this context clearly corresponds to the step of the range to create or to iterate over.
> Essentially this is a syntactic sugar that makes it easy to create ranges with a step ≠ 1. What do you think?
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