[swift-evolution] proposal to add "in range" operator
Preston Sumner
preston.sumner at gmail.com
Tue Feb 2 11:56:06 CST 2016
You can do this:
let testValue = 0.3
// Using instance method.
if (0.0..<1.0).contains(testValue) {
print("Hello, world.")
}
// Using pattern matching operator.
if 0.0..<1.0 ~= testValue {
print("Hello, world.")
}
Preston
> On Feb 2, 2016, at 4:53 AM, Gmail 2 via swift-evolution <swift-evolution at swift.org> wrote:
>
> Hello everyone,
> I have a proposal to add an "in range” operator in swift.
>
> ##Current situation
>
> Checking whether a value is or not within a certain range now depends on the control flow you use. for switch-statement, it is intuitive; but it is not for if-statement.
>
> Example:
>
> let testValue = 0.3
>
> switch testValue {
> case 0.0..<1.0: do something...
> default: break
> }
>
> to write the same logic in if-statement, you have to write like this:
>
> if testValue >= 0.0 && testValue < 1.0 {
> do something...
> }
>
> The disadvantage here:
> 1. It’s wordy;
> 2. It’s risky to write the same variable name twice, typo can occur and be ignored;
> 3. It’s inconsistent with switch-statement.
>
> ##Proposed solution
>
> Introduce a new operator to check a variable against a range.
> Here is a drafted operator: ~ (infix operator)
> With ~, the above if-statement can be rewritten like:
>
> if testValue ~ 0.0..<1.0 {
> do something...
> }
>
> looks much better.
>
> What’s more, if combined with the draft proposal Generalized range operators in `for-in`loops and other purposes <https://github.com/apple/swift-evolution/pull/129>, this new operator would more powerful.
>
> Thanks for reading
> _______________________________________________
> swift-evolution mailing list
> swift-evolution at swift.org
> https://lists.swift.org/mailman/listinfo/swift-evolution
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