# [swift-evolution] Brainstorming: Optional sugar inferred map

Paul Ossenbruggen possen at gmail.com
Wed Jan 27 23:50:50 CST 2016

```Maybe something like this?

let n : Int? = 5

let r = n? + 5

> On Jan 27, 2016, at 9:46 PM, Thorsten Seitz <tseitz42 at icloud.com> wrote:
>
> Too much hidden magic IMO. This would mean loosing the benefits of optionals, i.e. making explicit where optional cases occur and that handling the missing case has to be considered.
>
> -Thorsten
>
> Am 28.01.2016 um 06:30 schrieb Craig Cruden via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>>:
>
>> Yes
>>> On 2016-01-28, at 12:28:40, Paul Ossenbruggen <possen at gmail.com <mailto:possen at gmail.com>> wrote:
>>>
>>> Trying to see if I got this. So the type of r would be Int? at the end of this? And if n were nil then r would be nil? Otherwise it r is 10?
>>>
>>>
>>>
>>>> On Jan 27, 2016, at 9:19 PM, Craig Cruden via swift-evolution <swift-evolution at swift.org <mailto:swift-evolution at swift.org>> wrote:
>>>>
>>>> Swift currently encourages a lot of conditional code - especially when it comes to optionals.  In most cases when you are computing etc. on an Optional you would expect that you would want an optional result and things to be able to use optionals.
>>>>
>>>> In another language I generally just `map` one optional to another - which may not be the most readable code to some not use to optionals.
>>>>
>>>> I was wondering if maybe an expression is not available that it would rewrite the syntax to map from one to another value.
>>>>
>>>> So things like:
>>>>
>>>> let n : Int? = 5
>>>>
>>>> let r = n + 5
>>>>
>>>> would actually compile as
>>>>
>>>> let r = n.map {\$0 + 5}
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>>
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