[swift-evolution] [Proposal] Scoped resources (like C# using statement)
Kevin Ballard
kevin at sb.org
Thu Dec 31 18:55:14 CST 2015
On Thu, Dec 31, 2015, at 04:46 PM, Joe Groff wrote:
>
>> On Dec 31, 2015, at 4:26 PM, Kevin Ballard <kevin at sb.org> wrote:
>>
>> On Thu, Dec 31, 2015, at 01:40 PM, Michel Fortin wrote:
>>> Le 30 déc. 2015 à 16:40, Kevin Ballard via swift-evolution <swift-
>>> evolution at swift.org> a écrit :
>>>> On Wed, Dec 30, 2015, at 01:33 PM, Joe Groff wrote:
>>>>> Another possibility I've thought of is defining `defer { val }` to
>>>>> guarantee that val remains alive until the defer fires on scope
>>>>> exit. That might let us leave `defer` as the one "guarantee
>>>>> something happens exactly at scope exit" language construct.
>>>>
>>>> Oh that's cute. I'd probably want to say `defer { _ = val }`
>>>> though, to make it obvious that this is intentional.
>>>
>>> Or you could make it even more obvious what this is by giving that
>>> feature a name. For instance:
>>>
>>> defer { _fixLifetime(val) }
>>>
>>> The good thing about this one is that it already works, because
>>> that's what `withExtendedLifetime` does internally. Also, if you
>>> search a bit, you'll end up here with a nice explanation of what
>>> that function does.
>>> https://github.com/apple/swift/blob/8d9ef80304d7b36e13619ea50e6e76f3ec9221ba/stdlib/public/core/LifetimeManager.swift#L45
>>>
>>> So why not simply remove the underscore?
>>
>> Because it's not a very good API? Having some magic function called
>> `fixLifetime()` that keeps values alive is a little weird.
>> `withExtendedLifetime()` is also slightly weird, but it makes more
>> sense than fixLifetime() does, since withExtendedLifetime() is the
>> specific solution to the problem of "I need to ensure this value
>> remains alive for this entire scope because reasons".
>>
>> I'd much rather just see the syntax `_ = val` be converted into
>> `Builtin.fixLifetime(val)` because the only reason to write an
>> expression like that is because you want to make sure the value is
>> still alive at that point (that and because it's not unreasonable for
>> people to assume that `_ = val` will keep the value alive, so it
>> would be nice to make that assumption actually be correct).
>
> I don't think this is obviously true. `val` could be a computed
> property you just want to force the side effects for. (Computed
> properties with side effects maybe aren't a great idea, but there are
> some in AppKit/UIKit.)
I see two possibilities here:
1. If it's a computed property, fix the lifetime of the return value
anyway. I don't think this is particularly helpful though, although
all it would do in practice is prevent early-release if the computed
property is inlined, or
2. If it's a computed property, just don't fix the lifetime. It seems
fine to me to say `_ = localVar` has the implicit side-effect of
fixing the lifetime of localVar, and if you say `_ =
computedProperty` then that's just the pre-existing behavior of
evaluating the computed property for its side-effects. No need to fix
the lifetime of the computed property result.
Incidentally, does it makes sense to talk about fixing the lifetime of
stored properties? I assume that only really matters for local
variables, because stored properties are tied to `self`.
-Kevin
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <https://lists.swift.org/pipermail/swift-evolution/attachments/20151231/c811386a/attachment.html>
More information about the swift-evolution
mailing list