[swift-evolution] Shift operator: the type of the second operand
Jeremy Pereira
jeremy.j.pereira at googlemail.com
Fri Dec 18 05:55:38 CST 2015
These are the definitions of the right shift operators
public func >>(lhs: Int8, rhs: Int8) -> Int8
public func >>(lhs: Int, rhs: Int) -> Int
public func >>(lhs: UInt, rhs: UInt) -> UInt
public func >>(lhs: Int64, rhs: Int64) -> Int64
public func >>(lhs: UInt64, rhs: UInt64) -> UInt64
public func >>(lhs: UInt8, rhs: UInt8) -> UInt8
public func >>(lhs: UInt16, rhs: UInt16) -> UInt16
public func >>(lhs: Int16, rhs: Int16) -> Int16
public func >>(lhs: Int32, rhs: Int32) -> Int32
public func >>(lhs: UInt32, rhs: UInt32) -> UInt32
Note that both left and right hand side are of the same type. In my opinion, rhs, which represents the number of bits to shift, should always be an Int e.g.
public func >>(lhs: UInt64, rhs: Int) -> UInt64
The two operands are fundamentally different, the left hand one is conceptually an array of bits and the right hand one is conceptually a count.
The current definitions mean that I almost always have to do a cast on the right operand with shift operations. e.g. the following snippet that converts a UInt64 into an array of boolean values.
let aNumber: UInt64 = 0x123456
var numberAsBits: [Bool] = [];
for i in 0 ..< 64
{
numberAsBits.append((aNumber >> i) & 1 != 0); // Error because i needs to be cast to a UInt64
}
I would like additional versions of the shift operator where rhs is an Int please.
Needless to say, the same applies to the left shift operators.
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