[swift-evolution] Spread Operator as Shorthand for Map
Al Skipp
al_skipp at fastmail.fm
Wed Dec 16 09:23:22 CST 2015
> On 16 Dec 2015, at 12:47, Sean Kosanovich via swift-evolution <swift-evolution at swift.org> wrote:
>
> As a Groovy user, I really enjoy the shorthand Spread Operator over the Collect Closure (Map is the equivalent in Swift).
>
> Consider the following Swift code:
>
> struct Car {
> let make: String
> let model: String
> }
>
> let cars = [Car(make: "Jeep", model: "Grand Cherokee"), Car(make: "Dodge", model: "Challenger")]
> let makes = cars.map() { $0.make }
>
>
>
> Now consider the same code using a Spread Operator:
>
> let makes = cars*.make
I think there is a tension in Swift between its object oriented nature and higher-order functions which leads to a lot of repetition of { $0.property }
In this example:
cars.map { $0.make }
I’d like to write the following, but ‘make’ is a member, not a free function:
cars.map(make)
Is anyone else irked by the preponderance of { $0.property } in Swift (or is it just me being grumpy)? Not sure what the solution would be, but I can’t say I’m keen on the suggestion of:
cars*.make
It’s too mysterious.
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