[swift-evolution] [Pitch] Simpler interpretation of a reference to a generic type with no arguments

Dave Abrahams dabrahams at apple.com
Tue Jun 28 13:13:06 CDT 2016


on Thu Jun 23 2016, Slava Pestov <swift-evolution at swift.org> wrote:

> Simpler interpretation of a reference to a generic type with no
> arguments
>
> Proposal: SE-9999
> <https://github.com/slavapestov/swift-evolution/blob/silly-proposals/proposals/9999-simplify-unbound-generic-type.md>
> Author: Slava Pestov <https://github.com/slavapestov>
> Status: Awaiting review
> Review manager: TBD
>  <https://github.com/slavapestov/swift-evolution/tree/silly-proposals/proposals#introduction>Introduction
>
> This proposal cleans up the semantics of a reference to a generic type
> when no generic arguments are applied.
>
> Swift-evolution thread: Discussion thread topic for that proposal
> <http://news.gmane.org/gmane.comp.lang.swift.evolution>
>  <https://github.com/slavapestov/swift-evolution/tree/silly-proposals/proposals#motivation>Motivation
>
> Right now, we allow a generic type to be referenced with no generic
> arguments applied in a handful of special cases. The two primary rules
> here are the following:
>
> If the scope from which the reference is made is nested inside the
> definition of the type or an extension thereof, omitting generic
> arguments just means to implicitly apply the arguments from context.
>
> For example,
>
> struct GenericBox<Contents> {
>   let contents: Contents
>
>   // Equivalent to: func clone() -> GenericBox<Contents>
>   func clone() -> GenericBox {
>     return GenericBox(contents: contents)
>   }
> }
>
> extension GenericBox {
>   func print() {
>     // Equivalent to: let cloned: GenericBox<Contents>
>     let cloned: GenericBox = clone()
>     print(cloned.contents)
>   }
> }
> If the type is referenced from an unrelated scope, we attempt to infer
> the generic parameters.
>
> For example,
>
> func makeABox() -> GenericBox<Int> {
>   // Equivalent to: GenericBox<Int>(contents: 123)
>   return GenericBox(contents: 123)
> }
> The problem appears when the user expects the second behavior, but
> instead encounters the first. For example, the following does not type
> check:
>
> extension GenericBox {
>
>   func transform<T>(f: Contents -> T) -> GenericBox<T> {
>     // We resolve 'GenericBox' as 'GenericBox<Contents>', rather than
>     // inferring the type parameter
>     return GenericBox(contents: f(contents))
>   }
> }
>  <https://github.com/slavapestov/swift-evolution/tree/silly-proposals/proposals#proposed-solution>Proposed
> solution
>
> The proposed solution is to remove the first rule altogether. If the
> generic parameters cannot be inferred from context, they must be
> specified explicitly with the usual Type<Args...> syntax.

SGTM.  I've always found this shorthand to be somewhat surprising,
including in C++ where (IIUC) it originated.


-- 
Dave



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